ln(2x)+5y^2+7z=0

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Solution for ln(2x)+5y^2+7z=0 equation:


Simplifying
ln(2x) + 5y2 + 7z = 0

Remove parenthesis around (2x)
ln * 2x + 5y2 + 7z = 0

Reorder the terms for easier multiplication:
2ln * x + 5y2 + 7z = 0

Multiply ln * x
2lnx + 5y2 + 7z = 0

Solving
2lnx + 5y2 + 7z = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-5y2' to each side of the equation.
2lnx + 5y2 + -5y2 + 7z = 0 + -5y2

Combine like terms: 5y2 + -5y2 = 0
2lnx + 0 + 7z = 0 + -5y2
2lnx + 7z = 0 + -5y2
Remove the zero:
2lnx + 7z = -5y2

Add '-7z' to each side of the equation.
2lnx + 7z + -7z = -5y2 + -7z

Combine like terms: 7z + -7z = 0
2lnx + 0 = -5y2 + -7z
2lnx = -5y2 + -7z

Divide each side by '2nx'.
l = -2.5n-1x-1y2 + -3.5n-1x-1z

Simplifying
l = -2.5n-1x-1y2 + -3.5n-1x-1z

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